言葉にできるは武器なるらしい

言葉に文字に残していきます何事も。いつかきっと誰かの役に立つはずだから。

【SQLSERVER】「AAA」というカラム名を持つテーブルを検索したい

SQLSERVER】「AAA」というカラム名を持つテーブルを検索したい

そんな時はこれ。

USE DBname

SELECT
d.name as tablename ,
a.colorder as columnNo,
a.name as columnName,
(case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end) as mark,
(case when (SELECT count(*) FROM sysobjects
WHERE (name in
(SELECT name FROM sysindexes
WHERE (id = a.id) AND (indid in
(SELECT indid FROM sysindexkeys
WHERE (id = a.id) AND (colid in
(SELECT colid FROM syscolumns
WHERE (id = a.id) AND (name = a.name))
)))))
AND (xtype = 'PK'))>0 then '√' else '' end) as KeyName,
b.name as typename,
a.length as bytelength,
COLUMNPROPERTY(a.id,a.name,'PRECISION') as len_length,
isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0) as dimit,
(case when a.isnullable=1 then '√'else '' end) as ifcannull,
isnull(e.text,'') as defaultResult--,
FROM syscolumns a left join systypes b
on a.xtype=b.xusertype
inner join sysobjects d
on a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join syscomments e
on a.cdefault=e.id
where a.name like '%AAA%' --検索したい文字列
order by a.id,a.colorder

 


ちなみに
「指定したカラム名を持つテーブルを検索する」
というもっと簡単っぽいやりかたも検索したら出てきた。
http://sql55.com/query/search-tables-by-column-name.php